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LEXUS Originali dalis · OE

Originalios dalys tiekiamos gamintojo pakuotėje. Nuotraukos gamintojo kataloge nepateikiamos.

LEXUSOE

SILENTBLOCK

5220560050
GamintojasLEXUS
Gamintojo nr.5220560050
Kainoraštis atnaujintas2026-07-17
91.58 €su PVM
75.69 € be PVM · vnt.
On order from manufacturer
Delivery 3–10 d.d. · apmokėjus iš anksto
Nauja, gamintojo pakuotėjePaštomatas, kurjeris, atsiėmimasGamintojo užsakoma pagal jūsų automobilį

Pakaitiniai analogai

Kitų gamintojų dalys su tuo pačiu OE numeriu — dažnai 30–60 % pigiau, su kainomis ir likučiais.

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Gretimos LEXUS pozicijos

To paties kainoraščio numeriai — dažnai tos pačios grupės dalys.

About OE code 5220560050

5220560050 — is an original manufacturer (OE) number from LEXUS, for SILENTBLOCK. An OE number is the car manufacturer’s own part code — it identifies the part unambiguously, without mistakes over make, model or year. Below you can compare this original part with 1 aftermarket equivalents and choose by price and delivery time.

Make
LEXUS
OE code
5220560050
Name
SILENTBLOCK
Aftermarket offers
1
Price from
91.58 €

Frequently asked questions

Is LEXUS 5220560050 an original part?

Yes. This is an item from the manufacturer’s price list with an original LEXUS number, not a substitute. It is ordered directly from the manufacturer’s dealer.

How do I know whether 5220560050 fits my car?

Compare the code with the one on the old part or on the dealer’s invoice. If they match, the part fits. Not sure? Send us the VIN and we will check for you.

How much does 5220560050?

Currently 91.58 € including VAT. The price comes straight from the manufacturer’s price list and updates automatically.

Is there a cheaper alternative?

Yes — for this code we show 1 aftermarket offers with supplier prices and lead times. You will find them on this page.

How soon will I get it?

The lead time for this part is 3–10 d.d.. Aftermarket parts held in a supplier’s warehouse ship the same or the next working day.

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